Codeup——599 | 问题 A: Speech Patterns (25)

题目描述

People often have a preference among synonyms of the same word. For example, some may prefer “the police”, while others may prefer “the cops”. Analyzing such patterns can help to narrow down a speaker’s identity, which is useful when validating, for example, whether it’s still the same person behind an online avatar.

Now given a paragraph of text sampled from someone’s speech, can you find the person’s most commonly used word?

输入

Each input file contains one test case. For each case, there is one line of text no more than 1048576 characters in length, terminated by a carriage return ‘\n’. The input contains at least one alphanumerical character, i.e., one character from the set [0-9 A-Z a-z].

输出

For each test case, print in one line the most commonly occurring word in the input text, followed by a space and the number of times it has occurred in the input. If there are more than one such words, print the lexicographically smallest one. The word should be printed in all lower case. Here a “word” is defined as a continuous sequence of alphanumerical characters separated by non-alphanumerical characters or the line beginning/end.

Note that words are case insensitive.

样例输入

Can1: “Can a can can a can? It can!”

样例输出

can 5

#include <iostream>
#include <string>
#include <map>
#include <cctype>
using namespace std;

int main()
{
    
    
	string s,word,result;	//s为句子，word为句子中的单词，result为出现最多的单词
	map<string,int> mp;	//单词数
	map<string,bool> hashTable;	//单词的哈希表
	int i,max;
	while(getline(cin,s)){
    
    
		for(i=0;i<s.length();i++){
    
    
			if(isalpha(s[i]))	//如果是大写字母则转换成小写字母
				if(isupper(s[i]))
					s[i]=tolower(s[i]);
			if(isalnum(s[i]))	//从句子中获得单词
				word.push_back(s[i]);
			else	//如果是其它符号，说明不是单词，也表示这个单词已经操作过了，将word置空
				word.clear();
			if(!word.empty()&&!isalnum(s[i+1])){
    
    	//表示输入的单词完整了，则对其进行操作
				if(hashTable[word]==false){
    
    	//该单词首次出现
					mp[word]=1;	
					hashTable[word]=true;
				}
				else	//该单词曾经出现，则将其数量直接加1即可
					mp[word]++;
			}
		}
		max=0;
		for(map<string,int>::iterator it=mp.begin();it!=mp.end();it++)
			if(it->second>max){
    
    	//找到单词数出现最多的那一个
				result=it->first;
				max=it->second;
			}
		cout <<result<<" "<<max<<endl;
	}	
	return 0;
}