洛谷P1089津津的储蓄计划题解--zhengjun

题面传送门

思路

一道模拟题，注意下细节

代码

#include<bits/stdc++.h>
int s,h;
int main(){
    int x;
    for(int i=1; i<=12; i++){
        scanf("%d",&x);
        s=s-x+300;
        if(s<0){
            printf("-%d",i);
            return 0;
        } 
		else h+=s/100,s%=100;
    }
    printf("%d\n",120*h+s);
    return 0;
}

谢谢–zhengjun