树的输入、存储与遍历

问题描述:输入一棵二叉树,使用二叉链表结构存储二叉树,并用递归方法输出先序、中序、后序三种遍历结果。


#include<iostream>
#include<cstdlib>
using namespace std;
typedef struct BiTNode {
	char data;
	BiTNode *lchild, *rchild;
}BiTNode,*BiTree;

void CreateBiTree(BiTree &T)
{//以先序输入数据
	char ch;
	ch=getchar();
	if(ch==' ') T=NULL;
	else {
		if(!(T=(BiTNode *)malloc(sizeof(BiTNode)))) exit(0);
		T->data = ch;
		CreateBiTree(T->lchild);
		CreateBiTree(T->rchild);
	}
}

void PreOrderTraverse(BiTree &T) 
{//先序遍历
	if(T==NULL) return;
	if(T->data!=' ') cout<<T->data;
	PreOrderTraverse(T->lchild);
	PreOrderTraverse(T->rchild);
}

void InOrderTraverse(BiTree &T) 
{//中序遍历
	if(T==NULL) return;
	InOrderTraverse(T->lchild);
	if(T->data!=' ') cout<<T->data;
	InOrderTraverse(T->rchild);
}

void PostOrderTraverse(BiTree &T)
{//后序遍历
	if(T==NULL) return;
	PostOrderTraverse(T->lchild);
	PostOrderTraverse(T->rchild);
	if(T->data!=' ') cout<<T->data;
}

int main()
{
	BiTree T;
	cout<<"Enter the numbers(Preorder):"<<endl;
	CreateBiTree(T);
	cout<<"The Preorder is:"<<endl;
	PreOrderTraverse(T);
	cout<<endl;
	cout<<"The Inorder is:"<<endl;
	InOrderTraverse(T);
    cout<<endl;
	cout<<"The Posteorder is:"<<endl;
	PostOrderTraverse(T);
	cout<<endl;
	return 0;
}


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转载自blog.csdn.net/u014304560/article/details/48792521