样例(可复制)
4
29
5
elo nov
tam
hel mar
may
115
13
注意点
- 13的倍数不需要输出个位的“tret”,比如13为“tam”,而非"tam tret"
- 使用打表的方式,数字到字符串的映射使用string的numtostr完成,字符串到数字的映射使用map的strtonum完成
#include<bits/stdc++.h>
using namespace std;
string low[13]={"tret","jan","feb","mar","apr","may","jun","jly","aug","sep","oct","nov","dec"};
string high[13]={"tret","tam","hel","maa","huh","tou","kes","hei","elo","syy","lok","mer","jou"};
string numtostr[170];
map<string,int> strtonum;
void init(){
for(int i=0;i<13;i++){
numtostr[i]=low[i];
strtonum[numtostr[i]]=i;
numtostr[13*i]=high[i];
strtonum[high[i]]=i*13;
}
for(int i=1;i<13;i++){
for(int j=1;j<13;j++){
string str=high[i]+" "+low[j];
numtostr[i*13+j]=str;
strtonum[str]=i*13+j;
}
}
}
int main(){
init();
int t;
scanf("%d%*c",&t);
while(t--){
string str;
getline(cin,str);
if(str[0]>='0'&&str[0]<='9'){
int num=0;
for(int i=0;i<str.size();i++)num=num*10+str[i]-'0';
cout<<numtostr[num]<<endl;
}else{
cout<<strtonum[str]<<endl;
}
}
return 0;
}