Chapter 1 Introduction to Computer Systems
Introduction to Computer Introduction Knowledge:
1. From top to bottom, the memory pyramid is: register, cache, main memory, disk, CD, tape
USB is a universal serial bus
2^64=2^4*2^60=16*10^?
Review: K is 2 to the power of 10 10 ^ 3
M is 2 to the 20th power 2 ^ 10 × 2 ^ 10 = 1024 × 1024 = 10 ^ 3 × 10 ^ 3 = 10 ^ 6
G is 2 to the power of 30 2 ^ 10 × 2 ^ 10 × 2 ^ 10 = 10 ^ 9
2^16 = 2^6×2^10 = 64k
2 ^ 32 = 4 × 2 ^ 30 = 4G
30H- 39H represents the ASCII encoding of numbers 0-9
61H represents the ASCII encoding of English a
41H means ASCII encoding of English A
Host, IO device
Host: main memory, CPU! Unlike traditional host chassis, this is logical
Assignment 1: Explain the following picture clearly (corresponding to the first 5 of the von Neumann system)
During the preview today, there was a question that was uncertain, and the result was really wrong! (My usual time, 555)
So I specifically recorded this question, what is the main test of this question is the storage unit
Storage unit: store a string of binary codes (each storage unit is assigned an address number), store all storage element sets of a storage word
(Original textbook: each storage element can register a binary code "0" or "1", it can be seen that a storage unit can store a string of binary code, which is called a storage word) So store a storage word The collection of all storage elements is the storage unit
Review the relevant knowledge of the textbook: main memory-> main memory includes storage body M, various logic components and control circuits, etc. The storage body is composed of many storage units, and the storage unit contains several storage elements (or storage primitives, storage Yuan), each storage element can register a binary code "0" or "1". It can be seen that a storage unit can store a string of binary codes, which is called a storage word, and the number of bits of the string of binary codes becomes the storage word length.
