HDU 1276(士兵队列训练问题)

基础题,暴力搜索即可,详细见注释。

#include <iostream>
using namespace std;
const int MAXM = 5005;

struct soldier //士兵
{
	int num; //最初编号
}s[MAXM];

int main()
{
	int N;
	cin >> N;
	while (N--)
	{
		int M;
		cin >> M;
		for (int i = 1; i <= M; i++) //存储原始编号
		{
			s[i].num = i;
		}
		int total = M; //队伍中剩余人数
		int interval = 2; //报数间隔
		int now = 0; //当前报数
		while (total > 3)
		{
			for (int i = 1; i <= M; i++) //按照间隔出列
			{
				if (s[i].num != 0) //士兵未出列
					++now;
				if (now == interval)
				{
					s[i].num = 0; //士兵出列
					now = 0;
				}
			}
			now = 0;
			total = 0;
			for (int i = 1; i <= M; i++) //计算剩余人数
			{
				if (s[i].num != 0)
					++total;
			}
			if (interval == 2) //更改报数间隔
				interval = 3;
			else
				interval = 2;
		}
		int temp = 1; //当前输出人数
		for (int i = 1; i <= M; i++)
		{
			if (s[i].num != 0)
			{
				if (temp < total)
				{
					cout << s[i].num << " ";
					++temp;
				}
				else
					cout << s[i].num << endl;
			}
		}
	}
	return 0;
}

继续加油。

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转载自blog.csdn.net/Intelligence1028/article/details/104831321