#include <stdio.h>
void main() {
int i, t = 1;
float n, sum = 0;
for (i = 1; i <= 101; i += 2) {
n = (1.0 / i) * t;
sum += n;
t = -t;
}
printf("%.2f", sum);
}
分数求和:1-1/3+1/5-1/7+…-1/99+1/101。
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