题目描述
给定一个数组A[0,1,...,n-1],请构建一个数组B[0,1,...,n-1],其中B中的元素B[i]=A[0]*A[1]*...*A[i-1]*A[i+1]*...*A[n-1]。不能使用除法。(注意:规定B[0] = A[1] * A[2] * ... * A[n-1],B[n-1] = A[0] * A[1] * ... * A[n-2];)
解法一:反向法
# -*- coding:utf-8 -*-
class Solution:
def multiply(self, A):
# write code here
if not A:
return []
num = len(A)
B = [None]*num
B[0] = 1
for i in range(1,num):
B[i] = B[i-1]*A[i-1]
temp = 1
for i in range(num-2,-1,-1):
temp *= A[i+1]
B[i] *= temp
return B