/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
TreeNode* func(vector<int>& preorder, int start, int end) {
if (start>end){ return NULL;}
TreeNode *root = new TreeNode(preorder[start]);
int mid = -1;
for(int i=start+1;i<=end;i++){
if (preorder[start]<preorder[i]){
mid = i;
break;
}
}
if (mid == -1){// not find mid, then all is left parts
root->left = func(preorder, start+1, end);
return root;
}
else{
root->left = func(preorder, start+1, mid-1);
root->right = func(preorder, mid, end);
return root;
}
}
TreeNode* bstFromPreorder(vector<int>& preorder) {
return func(preorder, 0, preorder.size()-1);
}
};
1008. Construct Binary Search Tree from Preorder Traversal
猜你喜欢
转载自blog.csdn.net/zeroQiaoba/article/details/104692597
今日推荐
周排行