poj1721

题解:

直接暴力循环节

然后再做几次

代码:

#include<cstdio>
#include<cstring>
#include<algorithm>
#include<cmath>
const int N=1005; 
int n,s,p[N],a[N],B[N];  
void GetNext(int n)  
{  
    for (int i=1;i<=n;i++)B[i]=a[a[i]];  
    for (int i=1;i<=n;i++)a[i]=B[i];  
}  
int IsSame(int n)  
{  
    for (int i=1;i<=n;i++)  
     if (B[i]!=p[i])return 0;  
    return 1;  
}  
int main()  
{  
    while (~scanf("%d%d",&n,&s))  
     {   
        for (int i=1;i<=n;i++)scanf("%d",&p[i]),a[i]=p[i];
        int res;  
        for (res=1;;res++)  
         {  
            GetNext(n);  
            if (IsSame(n))break;  
         }  
        int m=res-s%res;  
        while (m--)GetNext(n);  
        for (int i=1;i<=n;i++)printf("%d\n",B[i]);  
     }  
    return 0;  
}  

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转载自www.cnblogs.com/xuanyiming/p/8977248.html