题目描述
Given a non-empty array containing only positive integers, find if the array can be partitioned into two subsets such that the sum of elements in both subsets is equal.
Note:
Each of the array element will not exceed 100.
The array size will not exceed 200.
Example 1:
Input: [1, 5, 11, 5]
Output: true
Explanation: The array can be partitioned as [1, 5, 5] and [11].
Example 2:
Input: [1, 2, 3, 5]
Output: false
Explanation: The array cannot be partitioned into equal sum subsets.
思路
记忆化搜索超时了。
递归,想了很久。考虑到数据范围和数组长度,target 在 10^4 范围。每次新增加一个数字时,从之前所有能组成的数字里,给当前能新组成的数字标记。
代码
class Solution {
public:
bool canPartition(vector<int>& nums) {
int n = nums.size();
int sum = 0;
for (int i=0; i<n; ++i) {
sum += nums[i];
}
if (sum % 2) return 0;
sum /= 2;
vector<int> dp(sum+1, 0);
dp[0] = 1;
for (int i=0; i<n; ++i) {
for (int j=sum; j>=0; --j) {
int tmp = j + nums[i];
if (tmp > sum) continue;
if (dp[j]) dp[tmp] = 1;
if (dp[sum]) return true;
}
}
return dp[sum];
}
};
好烦啊。。。。今天。。。
这是一道去年做过的题了。。貌似。。懒得更新了。