poj1008

#include<iostream>
#include<string>
using namespace std;
int main()
{
   string cale1[] = {"pop", "no", "zip", "zotz", "tzec", "xul", "yoxkin", "mol", "chen", "yax", "zac", "ceh", "mac", "kankin", "muan", "pax", "koyab", "cumhu", "uayet"};
   string cale2[] = {"imix", "ik", "akbal", "kan", "chicchan", "cimi", "manik", "lamat", "muluk", "ok", "chuen", "eb", "ben", "ix", "mem", "cib", "caban", "eznab", "canac", "ahau"};
    int m=0,n=0;
    int year;
    int day;
    char s;
    string mon;
    int size;
    cin>>size;
    int num[size];
    for(int i=0;i<size;i++)
    {
        cin>>day>>s>>mon>>year;
        for(m=0;m<19;m++)
        {
            if(mon==cale1[m])
                num[i]=day+m*20+365*year;

        }
    }
    cout<<size<<endl;
    for(int j=0;j<size;j++)
    {
        year=num[j]/260;
        n=num[j]%20;
        day=num[j]%13+1;
        cout<<day<<" "<<cale2[n]<<" "<<year<<endl;
    }
    return 0;
}

明白如何转换即可。先把前一种日期总日子数算出来再计算转为第二种。