刷题--复杂链表的复制

输入一个复杂链表(每个节点中有节点值,以及两个指针,一个指向下一个节点,另一个特殊指针指向任意一个节点),返回结果为复制后复杂链表的head。(注意,输出结果中请不要返回参数中的节点引用,否则判题程序会直接返回空)

第一反应:分两步。第一步考虑next,第二步考虑random。利用哈希表建立映射关系。

# -*- coding:utf-8 -*-
# class RandomListNode:
#     def __init__(self, x):
#         self.label = x
#         self.next = None
#         self.random = None
class Solution:
    # 返回 RandomListNode
    def Clone(self, pHead):
        # write code here
        if pHead:
            p1 = pHead
            p2 = RandomListNode(p1.label)
            pHeadNew = p2
            hashMap = {}

            while p1.next:
                hashMap[p1] = p2
                p2.next = RandomListNode(p1.next.label)
                p1 = p1.next
                p2 = p2.next

            hashMap[p1] = p2
            p1 = pHead
            p2 = pHeadNew

            while p1:
                if p1.random in hashMap:
                    p2.random = hashMap[p1.random]

                p1 = p1.next
                p2 = p2.next

            return pHeadNew
        else:
            return None

进阶版:将复制的每个结点接在对应原始结点的后面,复制结点random指针与原始结点random指针指向的位置应该是相邻的,最后将链表拆为原始链表和复制链表。

# -*- coding:utf-8 -*-
# class RandomListNode:
#     def __init__(self, x):
#         self.label = x
#         self.next = None
#         self.random = None
class Solution:
    # 返回 RandomListNode
    def Clone(self, pHead):
        # write code here
        if pHead:
            p1 = pHead

            while p1:
                p2 = RandomListNode(p1.label)
                p2.next = p1.next
                p1.next = p2
                p1 = p2.next

            p1 = pHead

            while p1:
                p2 = p1.next

                if p1.random:
                    p2.random = p1.random.next

                p1 = p2.next

            p1 = pHead
            pHeadNew = p2 = p1.next
            p1.next = p2.next
            p1 = p1.next

            while p1:
                p2.next = p1.next
                p2 = p2.next
                p1.next = p2.next
                p1 = p1.next

            return pHeadNew
        else:
            return None

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转载自blog.csdn.net/treasure_z/article/details/80258900