Codeforces Round #619 (Div. 2)_A. Three Strings(C++_模拟)

You are given three strings $a$, $b$ and $c$ of the same length $n$. The strings consist of lowercase English letters only. The $i$-th letter of $a$ is $a_i$, the $i$-th letter of $b$ is $b_i$, the $i$-th letter of $c$ is $c_i$.

For every $i$ ( $1 \leq i \leq n$) you must swap (i.e. exchange) $c_i$ with either $a_i$ or $b_i$. So in total you’ll perform exactly $n$ swap operations, each of them either $c_i \leftrightarrow a_i$ or $c_i \leftrightarrow b_i$ ( $i$ iterates over all integers between $1$ and $n$, inclusive).

For example, if $a$ is “code”, $b$ is “true”, and $c$ is “help”, you can make $c$ equal to “crue” taking the $1$-st and the $4$-th letters from $a$ and the others from $b$. In this way $a$ becomes “hodp” and $b$ becomes “tele”.

Is it possible that after these swaps the string $a$ becomes exactly the same as the string $b$?

Input

The input consists of multiple test cases. The first line contains a single integer $t$ ( $1 \leq t \leq 100$) — the number of test cases. The description of the test cases follows.

The first line of each test case contains a string of lowercase English letters $a$.

The second line of each test case contains a string of lowercase English letters $b$.

The third line of each test case contains a string of lowercase English letters $c$.

It is guaranteed that in each test case these three strings are non-empty and have the same length, which is not exceeding $100$.

Output

Print $t$ lines with answers for all test cases. For each test case:

If it is possible to make string $a$ equal to string $b$ print “YES” (without quotes), otherwise print “NO” (without quotes).

You can print either lowercase or uppercase letters in the answers.

Example

Input

4
aaa
bbb
ccc
abc
bca
bca
aabb
bbaa
baba
imi
mii
iim

Output

NO
YES
YES
NO

Note

In the first test case, it is impossible to do the swaps so that string $a$ becomes exactly the same as string $b$.

In the second test case, you should swap $c_i$ with $a_i$ for all possible $i$. After the swaps $a$ becomes “bca”, $b$ becomes “bca” and $c$ becomes “abc”. Here the strings $a$ and $b$ are equal.

In the third test case, you should swap $c_1$ with $a_1$, $c_2$ with $b_2$, $c_3$ with $b_3$ and $c_4$ with $a_4$. Then string $a$ becomes “baba”, string $b$ becomes “baba” and string $c$ becomes “abab”. Here the strings $a$ and $b$ are equal.

In the fourth test case, it is impossible to do the swaps so that string $a$ becomes exactly the same as string $b$.

Process

Compare $c_i$ and $a_i$ , if $a_i$ and $c_i$ are equal, we need to swap $c_i$ with $b_i$ to make $a_i$ and $b_i$ are equal. If the comparision shows that $a_i$ and $c_i$ are not equal, please compare $c_i$ and $b_i$. If $c_i$ and $b_i$ are equal, we should swap $c_i$ and $a_i$. As $i$ increases, keep comparing $c_i$ and $b_i$ or $a_i$ until they are not equal.

Code

    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n;
    	cin >> n;
    	for (int j = 1; j <= n; j++)
    	{
    		bool flag = 1;
    		string a, b, c;
    		cin >> a >> b >> c;
    		for (int i = 0; i < a.size(); i++)
    		{
    			char temp;
    			if (c[i] == a[i])
    			{
    				temp = c[i];
    				c[i] = b[i];
    				b[i] = temp;
    			}
    			else if (c[i] == b[i])
    			{
    				temp = c[i];
    				c[i] = a[i];
    				a[i] = temp;
    			}
    			else
    			{
    				flag = 0;
    				break;
    			}
    		}
    		if (flag)
    			cout << "YES" << endl;
    		else
    			cout << "NO" << endl;
    	}
    	return 0;
    }