Educational Codeforces Round 82 (Rated for Div. 2)_A. Erasing Zeroes(C++_模拟)

You are given a string $s$. Each character is either 0 or 1.
You want all 1’s in the string to form a contiguous subsegment. For example, if the string is 0, 1, 00111 or 01111100, then all 1’s form a contiguous subsegment, and if the string is 0101, 100001 or 11111111111101, then this condition is not met.
You may erase some (possibly none) 0’s from the string. What is the minimum number of 0’s that you have to erase?

Input

The first line contains one integer t(1≤t≤100) — the number of test cases.
Then t lines follow, each representing a test case. Each line contains one string s (1≤|s|≤100); each character of s is either 0 or 1.

Output

Print t integers, where the i-th integer is the answer to the i-th testcase (the minimum number of 0’s that you have to erase from s).

Example

Input

3
010011
0
1111000

Output

2
0
0

Note

In the first test case you have to delete the third and forth symbols from string 010011 (it turns into 0111).

Process

From the first ‘1’ to count, you should add it to ans, if you run into the next ‘1’. After this test case, please remember to make flag’value to ‘0’ every time. This my first codeforces-competition. When I saw the english problems, I’m too nervous to solve it. Please come on. I will do it, I just do it.

Code

    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n;
    	cin >> n;
    	for (int i = 1; i <= n; i++)
    	{
    		bool flag = 0;
    		string temp;
    		cin >> temp;
    		int num = 0, ans = 0;
    		for (int j = 0; j < temp.size(); j++)
    		{
    			if (flag == 0 && temp[j] == '1')
    			{
    				flag = 1;
    				continue;
    			}
    			if (flag == 1 && temp[j] == '1')
    			{
    				ans += num;
    				num = 0;
    				continue;
    			}
    			if (flag == 1)
    				num++;
    		}
    		cout << ans<<" ";
    	}
    	return 0;
    }