lua 实现位操作代码及案例

写到前面的话:
作者从毕业开始一直从事游戏开发,提供大量游戏实战模块代码及案例供大家学习与交流,希望以下知识可以带来一些帮助,如有任何疑问,请加群641792143交流与学习

 bit = bit or {}
    bit.data32 = {}
    
    for i=1,32 do
        bit.data32[i]=2^(32-i)
    end
    
    function bit._b2d(arg)
        local nr=0
        for i=1,32 do
            if arg[i] ==1 then
                nr=nr+bit.data32[i]
            end
        end
        return  nr
    end
    
    function bit._d2b(arg)
        arg = arg >= 0 and arg or (0xFFFFFFFF + arg + 1)
        local tr={}
        for i=1,32 do
            if arg >= bit.data32[i] then
                tr[i]=1
                arg=arg-bit.data32[i]
            else
                tr[i]=0
            end
        end
        return   tr
    end
    
    function    bit._and(a,b)
        local op1=bit._d2b(a)
        local op2=bit._d2b(b)
        local r={}
    
        for i=1,32 do
            if op1[i]==1 and op2[i]==1  then
                r[i]=1
            else
                r[i]=0
            end
        end
        return  bit._b2d(r)
    
    end
    
    function    bit._rshift(a,n)
        local op1=bit._d2b(a)
        n = n <= 32 and n or 32
        n = n >= 0 and n or 0
    
        for i=32, n+1, -1 do
            op1[i] = op1[i-n]
        end
        for i=1, n do
            op1[i] = 0
        end
    
        return  bit._b2d(op1)
    end
    
    function bit._not(a)
        local op1=bit._d2b(a)
        local r={}
    
        for i=1,32 do
            if  op1[i]==1   then
                r[i]=0
            else
                r[i]=1
            end
        end
        return bit._b2d(r)
    end
    
    function bit._or(a,b)
        local op1=bit._d2b(a)
        local op2=bit._d2b(b)
        local r={}
    
        for i=1,32 do
            if op1[i]==1 or op2[i]==1  then
                r[i]=1
            else
                r[i]=0
            end
        end
        return bit._b2d(r)
    end
 
    local a = 7
    
    local b = bit._d2b(a)
    
    
    for k,v in pairs(b) do
    	print(k,v)
    end
    
    print(bit._b2d(b))
发布了43 篇原创文章 · 获赞 1 · 访问量 2328

猜你喜欢

转载自blog.csdn.net/lpl312905509/article/details/94363343