写到前面的话:
作者从毕业开始一直从事游戏开发,提供大量游戏实战模块代码及案例供大家学习与交流,希望以下知识可以带来一些帮助,如有任何疑问,请加群641792143交流与学习
bit = bit or {}
bit.data32 = {}
for i=1,32 do
bit.data32[i]=2^(32-i)
end
function bit._b2d(arg)
local nr=0
for i=1,32 do
if arg[i] ==1 then
nr=nr+bit.data32[i]
end
end
return nr
end
function bit._d2b(arg)
arg = arg >= 0 and arg or (0xFFFFFFFF + arg + 1)
local tr={}
for i=1,32 do
if arg >= bit.data32[i] then
tr[i]=1
arg=arg-bit.data32[i]
else
tr[i]=0
end
end
return tr
end
function bit._and(a,b)
local op1=bit._d2b(a)
local op2=bit._d2b(b)
local r={}
for i=1,32 do
if op1[i]==1 and op2[i]==1 then
r[i]=1
else
r[i]=0
end
end
return bit._b2d(r)
end
function bit._rshift(a,n)
local op1=bit._d2b(a)
n = n <= 32 and n or 32
n = n >= 0 and n or 0
for i=32, n+1, -1 do
op1[i] = op1[i-n]
end
for i=1, n do
op1[i] = 0
end
return bit._b2d(op1)
end
function bit._not(a)
local op1=bit._d2b(a)
local r={}
for i=1,32 do
if op1[i]==1 then
r[i]=0
else
r[i]=1
end
end
return bit._b2d(r)
end
function bit._or(a,b)
local op1=bit._d2b(a)
local op2=bit._d2b(b)
local r={}
for i=1,32 do
if op1[i]==1 or op2[i]==1 then
r[i]=1
else
r[i]=0
end
end
return bit._b2d(r)
end
local a = 7
local b = bit._d2b(a)
for k,v in pairs(b) do
print(k,v)
end
print(bit._b2d(b))