python斐波那契数列

python斐波那契数列

递归方法:

   """斐波那契数列的递归计算"""
      def recur_fibo(num):
         if num<=1:
             return num
         else:
            return (recur_fibo(num-1)+recur_fibo(num-2))
             
      if __name__ == '__main__':
        number=int(input("请输入你要输出的斐波那契数列的项数"))
        if number>=0:
            for i in range(number):
               print(recur_fibo(i))
        else:
           print ("请输入正整数")

非递归方法:

def function(num):        
            """实现斐波那契数列函数"""
            number1=0    #第一项
            number2=1    #第二项
            count=2
            if num==1:
                print(number1)
            else:
                print(number1,",",number2,end=",")
        
                while count<num:
                    nth=number1+number2
                    print(nth,end=",")
        
                    number1=number2
                    number2=nth
                    count+=1    
        
        if __name__ == '__main__':
            number=int(input("请输入你要就算的斐波那契数列的项数"))
            if number>=0:
                function(number)
            else:
                print ("请输入一个正整数")

程序运行结果截图:
在这里插入图片描述

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转载自blog.csdn.net/adim__/article/details/102491059