Mr. West bought a new car! So he is travelling around the city.
One day he comes to a vertical corner. The street he is currently in has a width x, the street he wants to turn to has a width y. The car has a length l and a width d.
Can Mr. West go across the corner?
Input
Every line has four real numbers, x, y, l and w.
Proceed to the end of file.
Output
If he can go across the corner, print "yes". Print "no" otherwise.
Sample Input
10 6 13.5 4 10 6 14.5 4
Sample Output
yes no
题意：给你两个路口的宽和车的长和宽，问你能不能把车开过这个路口。
思路：盗用大佬的图片
尽可能的贴着墙壁来过弯，所以能推导出-x先增大后减小，所以用到了三分的知识，具体看代码。
AC代码：
#include <bits/stdc++.h>
typedef long long ll;
const double maxx=1e-6;
const double pi=acos(-1.0);
const int inf=0x3f3f3f3f;
using namespace std;
double x,y,l,w;
double sanfen(double jd)
{
return (-x+l*sin(jd)+w/cos(jd))/tan(jd);
}
int main()
{
while(cin>>x>>y>>l>>w)
{
double l=0,r=pi/2,mid,midr;
while(maxx+l<r)
{
mid=l+(r-l)/3;
midr=r-(r-l)/3;
if(sanfen(mid)>sanfen(midr))
r=midr;
else
l=mid;
}
if(sanfen(l)<y)
cout<<"yes"<<endl;
else
cout<<"no"<<endl;
}
return 0;
}