C语言 计算两个复数之积

题目描述

本题要求实现一个计算复数之积的简单函数。

函数接口定义：

struct complex multiply(struct complex x, struct complex y);

其中struct complex是复数结构体，其定义如下：

struct complex
{
int real;
int imag;
};

裁判测试程序样例：

#include <stdio.h>

struct complex
{
int real;
int imag;
};

struct complex multiply(struct complex x, struct complex y);

int main()
{
struct complex product, x, y;
scanf("%d%d%d%d", &x.real, &x.imag, &y.real, &y.imag);
product = multiply(x, y);
printf("(%d+%di) * (%d+%di) = %d + %di\n", x.real, x.imag, y.real, y.imag, product.real, product.imag);
return 0;
}
/* 你的代码将被嵌在这里 */

样例输入 Copy

3 4 5 6

样例输出 Copy

(3+4i) * (5+6i) = -9 + 38i

代码

struct complex multiply(struct complex x, struct complex y)
{
	
	struct complex answer;
	answer.real=x.real*y.real-x.imag*y.imag;
	answer.imag=x.imag*y.real+x.real*y.imag;
	return answer;
}