[Swift]LeetCode1318. 或运算的最小翻转次数 | Minimum Flips to Make a OR b Equal to c

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Given 3 positives numbers a, b and c. Return the minimum flips required in some bits of a and b to make ( a OR b == c ). (bitwise OR operation).
Flip operation consists of change any single bit 1 to 0 or change the bit 0 to 1 in their binary representation.

Example 1:

Input: a = 2, b = 6, c = 5
Output: 3
Explanation: After flips a = 1 , b = 4 , c = 5 such that (a OR b == c)
Example 2:

Input: a = 4, b = 2, c = 7
Output: 1
Example 3:

Input: a = 1, b = 2, c = 3
Output: 0
 

Constraints:

1 <= a <= 10^9
1 <= b <= 10^9
1 <= c <= 10^9


给你三个正整数 a、b 和 c。

你可以对 a 和 b 的二进制表示进行位翻转操作,返回能够使按位或运算   a OR b == c  成立的最小翻转次数。

「位翻转操作」是指将一个数的二进制表示任何单个位上的 1 变成 0 或者 0 变成 1 。

示例 1:

输入:a = 2, b = 6, c = 5
输出:3
解释:翻转后 a = 1 , b = 4 , c = 5 使得 a OR b == c
示例 2:

输入:a = 4, b = 2, c = 7
输出:1
示例 3:

输入:a = 1, b = 2, c = 3
输出:0
 

提示:

1 <= a <= 10^9
1 <= b <= 10^9
1 <= c <= 10^9

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转载自www.cnblogs.com/strengthen/p/12185583.html