Source:
Description:
People on Mars count their numbers with base 13:
- Zero on Earth is called "tret" on Mars.
- The numbers 1 to 12 on Earth is called "jan, feb, mar, apr, may, jun, jly, aug, sep, oct, nov, dec" on Mars, respectively.
- For the next higher digit, Mars people name the 12 numbers as "tam, hel, maa, huh, tou, kes, hei, elo, syy, lok, mer, jou", respectively.
For examples, the number 29 on Earth is called "hel mar" on Mars; and "elo nov" on Mars corresponds to 115 on Earth. In order to help communication between people from these two planets, you are supposed to write a program for mutual translation between Earth and Mars number systems.
Input Specification:
Each input file contains one test case. For each case, the first line contains a positive integer N (<). Then N lines follow, each contains a number in [0, 169), given either in the form of an Earth number, or that of Mars.
Output Specification:
For each number, print in a line the corresponding number in the other language.
Sample Input:
4 29 5 elo nov tam
Sample Output:
hel mar may 115 13
Keys:
- 哈希映射
Attention:
- getline()会吸收换行符
Code:
1 /* 2 题目大意: 3 4 */ 5 #include<cstdio> 6 #include<string> 7 #include<map> 8 #include<iostream> 9 using namespace std; 10 const int M=13; 11 map<string,int> earth; 12 string mars0[M]={"tret", "jan", "feb", "mar", "apr", "may", "jun", "jly", "aug", "sep", "oct", "nov", "dec"}; 13 string mars1[M]={"","tam", "hel", "maa", "huh", "tou", "kes", "hei", "elo", "syy", "lok", "mer", "jou"}; 14 15 int main() 16 { 17 #ifdef ONLINE_JUDGE 18 #else 19 freopen("Test.txt", "r", stdin); 20 #endif // ONLINE_JUDGE 21 22 for(int i=0; i<M; i++) 23 earth[mars0[i]]=i; 24 for(int i=1; i<M; i++) 25 earth[mars1[i]]=i*M; 26 27 int n; 28 scanf("%d\n", &n); 29 while(n--) 30 { 31 string s; 32 getline(cin,s); 33 if(s[0]<'0' || s[0]>'9') 34 { 35 if(s.size()==3) 36 printf("%d\n", earth[s]); 37 else 38 printf("%d\n", earth[s.substr(0,3)]+earth[s.substr(4,3)]); 39 } 40 else 41 { 42 int num = atoi(s.c_str()); 43 if(num%M!=0 && num/M!=0) 44 printf("%s %s\n", mars1[num/M].c_str(),mars0[num%M].c_str()); 45 else if(num/M!=0) 46 printf("%s\n", mars1[num/M].c_str()); 47 else 48 printf("%s\n", mars0[num%M].c_str()); 49 } 50 } 51 52 return 0; 53 }