(Easy) Detect Capital -LeetCode

Description:

Given a word, you need to judge whether the usage of capitals in it is right or not.

We define the usage of capitals in a word to be right when one of the following cases holds:

  1. All letters in this word are capitals, like "USA".
  2. All letters in this word are not capitals, like "leetcode".
  3. Only the first letter in this word is capital, like "Google".
Otherwise, we define that this word doesn't use capitals in a right way.

Example 1:

Input: "USA"
Output: True

Example 2:

Input: "FlaG"
Output: False

Note: The input will be a non-empty word consisting of uppercase and lowercase latin letters.

Accepted
90,478
Submissions
171,652

Solution:

class Solution {
    public boolean detectCapitalUse(String word) {
        
        //ASCII Code A-Z 65-90
        //           a-z 97-122
        
        
        if(word==null||word.length()==0){
            return true;
        }
        
        return (Lowercase_Check(word)||Upercase_Check(word)||First_Capital_Check(word));
        
    }
    
    public boolean Lowercase_Check(String word){
        
        for(int i = 0; i<word.length(); i++){
            
            if(!(word.charAt(i) >='a' && word.charAt(i) <='z')){
                
                return false;
            }
        }
        
        return true;
    }
    
     public boolean Upercase_Check(String word){
        
        for(int i = 0; i<word.length(); i++){
            
            if(!(word.charAt(i) >='A' && word.charAt(i) <='Z')){
                
                return false;
            }
        }
        
        return true;
    }
    
    public boolean First_Capital_Check(String word){
        
        
        if(word.charAt(0)>='A' && word.charAt(0)<= 'Z'){
            
            for(int i = 1; i<word.length(); i++){

                if(!( word.charAt(i) >='a' && word.charAt(i) <='z')){

                    return false;
                }
             }
            
            return true;
            
        }
        
        else{
            return false;
        }
        
        
    }
}

猜你喜欢

转载自www.cnblogs.com/codingyangmao/p/11394664.html