我在浏览网页时未能找到以下简单问题的解决方案:
如何使用顶点值绘制3D多边形(比如填充的矩形或三角形)? 我尝试过很多想法,但都失败了,请看:
from mpl_toolkits.mplot3d import Axes3D
from matplotlib.collections import PolyCollection
import matplotlib.pyplot as plt
fig = plt.figure()
ax = Axes3D(fig)
x = [0,1,1,0]
y = [0,0,1,1]
z = [0,1,0,1]
verts = [zip(x, y,z)]
ax.add_collection3d(PolyCollection(verts),zs=z)
plt.show()
上面的解决方案适用于Python 2,在使用python 3运行时出现错误TypeError: object of type 'zip' has no len()。
根据接受的答案更新:
import mpl_toolkits.mplot3d as a3
import matplotlib.colors as colors
import pylab as pl
import scipy as sp
ax = a3.Axes3D(pl.figure())
for i in range(10000):
vtx = sp.rand(3,3)
tri = a3.art3d.Poly3DCollection([vtx])
tri.set_color(colors.rgb2hex(sp.rand(3)))
tri.set_edgecolor('k')
ax.add_collection3d(tri)
pl.show()
结果如下:
我想你差不多了。 这是你想要的吗?
from mpl_toolkits.mplot3d import Axes3D
from mpl_toolkits.mplot3d.art3d import Poly3DCollection
import matplotlib.pyplot as plt
fig = plt.figure()
ax = Axes3D(fig)
x = [0,1,1,0]
y = [0,0,1,1]
z = [0,1,0,1]
verts = [list(zip(x,y,z))]
ax.add_collection3d(Poly3DCollection(verts))
plt.show()
您可能也对art3d.pathpatch_2d_to_3d感兴趣。