计算1-1/2+1/3-1/4+......+1/100的值

#include<stdio.h>
int main()
{
	int i=0;
	double sum=0.0;
	int flag=1;
	for(i=0;i<=100;i++)
	{
		sum=sum+flag*1.0/i;
		flag=-flag;
	}
	printf("%1f",sum);
	return 0;
}

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转载自blog.csdn.net/shoushou_/article/details/90106133