计算1/1-1/2+1/3-1/4+1/5-...-1/100的值

计算1/1-1/2+1/3-1/4+1/5-…-1/100的值

#include<stdio.h>

int main()
{
	int a=0;
	double sum=0.0;
	int b=1;
	for(a=1;a<=100;a++)
	{
		sum+=b*1.0/a;
		b=-b;
	}
	printf("%lf\n",sum);
	return 0;
}

菜菜的代码,希望能够帮助到你哟!

猜你喜欢

转载自blog.csdn.net/Sconnie/article/details/113069446
今日推荐