#include<stdio.h>
#include<stdlib.h>
main()
{
int i = 1;
double a=0;
for (i = 1.; i < 101; i++)
{
if (i % 2 == 1)
{
a = a +(double)1 / i;
}
else
a = a - (double)1 / i;
}
printf("%f", a);
system("pause");
return 0;
}
计算1/1-1/2+1/3-1/4+.....1/99-1/100的值
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转载自blog.csdn.net/qq940051592/article/details/84575661
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