jq上传图片

<!doctype html>
<html lang="en">
 <head>
  <meta charset="UTF-8">
  <meta name="Generator" content="EditPlus®">
  <meta name="Author" content="">
  <meta name="Keywords" content="">
  <meta name="Description" content="">
  <title>Document</title>
 </head>
 <script src="https://cdn.staticfile.org/jquery/3.3.1/jquery.min.js"></script>
 <body>
   <form action='' method='post' enctype="multipart/form-data" id='form1'>
       <input type='file' name='file'>
	   <button type='button' class='but'>上传</button>
   </form>
 </body>
 <script>
    $(function(){
	   $('.but').click(function(){
	      data = new FormData($('#form1')[0]); 
		  console.log(data);
		 // $.post('up.php',{p:2},function(data){
		 //    alert(data);
		//  })
		   $.ajax({  
            url: 'up.php',  
            type: 'POST',  
            data: data,  
            dataType: 'JSON',  
            cache: false,  
            processData: false,  //不处理发送的数据,因为data值是FormData对象,不需要对数据做处理 
            contentType: false   //不设置Content-type请求头
        }).done(function(ret){  
           console.log(ret);
        });  
	   })
	})
 </script>
</html>

up.php中

<?php

$filename='upload/'.time().substr($_FILES['file']['name'], strrpos($_FILES['file']['name'],'.')); 
$response = array();  
if(is_uploaded_file($_FILES['file']['tmp_name']))
{
	if(move_uploaded_file($_FILES['file']['tmp_name'],$filename))
	{	
		echo json_encode('成功'); 
	} 
	else 
	{
		echo json_encode('失败'); 
	} 
}

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转载自blog.csdn.net/qq_43632766/article/details/84647529
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