Python - List_Comprehension（列表解析式）

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a = [1,2,3,4,5,6,7,8,9]

我们要对a中的每个元素取平方：

1> square = [i ** 2 for i in a]

2> square = list(map(lambda x: x ** 2, a))

[ 一般情况下，使用列表解析式会比使用一些高阶函数更加简洁和容易理解 ]

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from pprint import pprint

number = range(3)
a = [str(i)+"***"+str(j) for i in number for j in number]
x,y,z = [list(i) for i in "ABC"]
pprint(a)
print(x,y,z)

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list.append(value)

list.pop(index)

list.pop()

list.remove(value) 

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a = sorted(Data,key=lambda x:x[1])

a = sorted(Data)

a = reversed(Data)

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列表的快速初始化：

a = [0]  * 10

>>> [0,0,0,0,0,0,0,0,0,0]