题目:一个数如果恰好等于它的因子之和,这个数就称为"完数"。例如 6=1+2+3.编程找出 1000 以内的所有完数。
public class WangDao {
public static void main(String[] args){
System.out.println("The perfact numbers between 1-1000 are: ");
for (int i = 1; i <= 1000; i++) {
int sum = 0;
for (int j = 1; j <= i/2+1; j++ ) {
if (i % j == 0) {
sum += j;
}
}
if (sum == i) {
System.out.println(i);
}
}
}
}