Vasya has several phone books, in which he recorded the telephone numbers of his friends. Each of his friends can have one or several phone numbers.
Vasya decided to organize information about the phone numbers of friends. You will be given n strings — all entries from Vasya's phone books. Each entry starts with a friend's name. Then follows the number of phone numbers in the current entry, and then the phone numbers themselves. It is possible that several identical phones are recorded in the same record.
Vasya also believes that if the phone number a is a suffix of the phone number b (that is, the number b ends up with a), and both numbers are written by Vasya as the phone numbers of the same person, then a is recorded without the city code and it should not be taken into account.
The task is to print organized information about the phone numbers of Vasya's friends. It is possible that two different people have the same number. If one person has two numbers x and y, and x is a suffix of y (that is, y ends in x), then you shouldn't print number x. If the number of a friend in the Vasya's phone books is recorded several times in the same format, it is necessary to take it into account exactly once.
Read the examples to understand statement and format of the output better.
Input
First line contains the integer n (1 ≤ n ≤ 20) — number of entries in Vasya's phone books.
The following n lines are followed by descriptions of the records in the format described in statement. Names of Vasya's friends are non-empty strings whose length does not exceed 10. They consists only of lowercase English letters. Number of phone numbers in one entry is not less than 1 is not more than 10. The telephone numbers consist of digits only. If you represent a phone number as a string, then its length will be in range from 1 to 10. Phone numbers can contain leading zeros.
Output
Print out the ordered information about the phone numbers of Vasya's friends. First output m — number of friends that are found in Vasya's phone books.
The following m lines must contain entries in the following format "name number_of_phone_numbers phone_numbers". Phone numbers should be separated by a space. Each record must contain all the phone numbers of current friend.
Entries can be displayed in arbitrary order, phone numbers for one record can also be printed in arbitrary order.
Examples
Input
2 ivan 1 00123 masha 1 00123
Output
2 masha 1 00123 ivan 1 00123
Input
3 karl 2 612 12 petr 1 12 katya 1 612
Output
3 katya 1 612 petr 1 12 karl 1 612
Input
4 ivan 3 123 123 456 ivan 2 456 456 ivan 8 789 3 23 6 56 9 89 2 dasha 2 23 789
Output
2 dasha 2 23 789 ivan 4 789 123 2 456
题意：给你一个N表示下边有N个字符串，每个字符串第一个表示这个朋友的名字，后边是这几个电话号码，每两个电话号码之间以空格隔开。然后是让你帮他整理手机号，如果a是b的后缀，那么就会删除a，让我们输出整理后的电话号。
考察到STL库的运用和模拟，我们定义一个map，map<string,set<string> > m，就可以存储每个名字和后边对应的手机号了。
#include<bits/stdc++.h>
using namespace std;
map<string,set<string> > m;
set<string> s;
vector<string> v;
map<string,int> vs , b;
int solove(string x)
{
int k = 1;
while(k <= x.length() - 1)
{
string s = x.substr(k);
k ++;
vs[s] = 1;
}
}
int main()
{
int t;
char str[300];
while(cin >> t)
{
int n;
while(t--)
{
cin >> str >> n;
s.insert(str);
for(int i = 0 ; i < n ; i ++)
{
string x;
cin >> x;
m[str].insert(x);
}
}
cout << m.size() << endl;
for(auto x : s)
{
cout << x << " " ;
v.clear();
vs.clear();
b.clear();
for(auto it : m[x])
solove(it);
for(auto it : m[x])
if(vs[it] == 1)
b[it] = 1;
for(auto it : m[x])
{
if(b[it] == 0)
v.push_back(it);
}
cout << v.size() << " ";
for(auto it : v)
cout << it << " ";
cout << endl;
}
}
return 0;
}