codeforces_273C

You have r red, g green and b blue balloons. To decorate a single table for the banquet you need exactly three balloons. Three balloons attached to some table shouldn't have the same color. What maximum number t of tables can be decorated if we know number of balloons of each color?

Your task is to write a program that for given values r, g and b will find the maximum number t of tables, that can be decorated in the required manner.

Input

The single line contains three integers r, g and b (0 ≤ r, g, b ≤ 2·109) — the number of red, green and blue baloons respectively. The numbers are separated by exactly one space.

Output

Print a single integer t — the maximum number of tables that can be decorated in the required manner.

    Sample test(s) 
  
      input 
    
5 4 3

      output 
    
4

      input 
    
1 1 1

      output 
    
1

      input 
    
2 3 3

      output 
    
2

Note

In the first sample you can decorate the tables with the following balloon sets: "rgg", "gbb", "brr", "rrg", where "r", "g" and "b" represent the red, green and blue balls, respectively.

首先要明白，当最大的气球数量的一半小于另外两种颜色的数量之和，肯定可以组成全部颜色数量之和/3,当最大的

气球数量的一半大于等于另外两种颜色的数量之和，全部组成为2+1，2为最多数量的颜色。

#include <iostream>
#include <cstdio>
#include <cstdio>
#include <algorithm>
using namespace std;

int main()
{
    long long a[3];
    scanf("%I64d%I64d%I64d",&a[0],&a[1],&a[2]);
    sort(a,a+3);
    long long ans=0;
    if((a[0]+a[1])<=a[2]/2)
    {
       ans=a[0]+a[1];
    }
    else
    {
        ans=(a[0]+a[1]+a[2])/3;
    }
    printf("%I64d\n",ans);
    return 0;
}

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