主要就是考虑到如何处理,把前导的连续字符放到原字符串末尾
就和处理环状的题类似,字符串开二倍
#include<algorithm>
#include<cstdio>
#include<cmath>
#include<iostream>
#include<cstring>
#include<set>
#include<vector>
#include<string>
using namespace std;
typedef long long ll;
const int N=1e6+10;
const int INF=1000000007;
const double eps=0.0000001;
int Manacher(string s) {
// Insert '#'
string t = "$#";
for (int i = 0; i < s.size(); ++i) {
t += s[i];
t += "#";
}
// Process t
vector<int> p(t.size(), 0);
int mx = 0, id = 0, resLen = 0, resCenter = 0;
//mx是回文串能延伸到最右端的位置
//id当前节点回文串的中心点位置
for (int i = 1; i < t.size(); ++i) {
p[i] = mx > i ? min(p[2 * id - i], mx - i) : 1;
while (t[i + p[i]] == t[i - p[i]]) ++p[i];
//变更中心点
if (mx < i + p[i]) {
mx = i + p[i];
id = i;
}
if (resLen < p[i]) {
resLen = p[i];
resCenter = i;
}
}
return resLen - 1;//重点
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
string s,str;
int ans,sum=0;
cin>>s;
int len=s.size();
s=s+s;
for(int i=0;i+len<s.size();i++)
{
str=s.substr(i,len);
ans=Manacher(str);
sum=max(ans,sum);
}
cout<<sum<<endl;
}