参考于这篇眨眼检测博客,在他原来的代码上的条件做了修改。https://blog.csdn.net/ctwy291314/article/details/81665328
谢谢这位大佬。
本来是想做睡觉检测的,但是我只能走到这一步了,希望有大佬可以帮助我实现闭眼7秒则程序会提示。
代码如下
from scipy.spatial import distance as dist```
from imutils.video import FileVideoStream
from imutils.video import VideoStream
from imutils import face_utils
import numpy as np
import argparse
import imutils
import time
import dlib
import cv2
def eye_aspect_ratio(eye):
A = dist.euclidean(eye[1], eye[5])
B = dist.euclidean(eye[2], eye[4])
C = dist.euclidean(eye[0], eye[3])
ear = (A + B) / (2.0 * C)
return ear
EYE_AR_THRESH = 0.2
EYE_AR_CONSEC_FRAMES = 3
COUNTER = 0
TOTAL = 0
print("[INFO] loading facial landmark predictor...")
detector = dlib.get_frontal_face_detector()
predictor = dlib.shape_predictor('shape_predictor_68_face_landmarks.dat')
(lStart, lEnd) = face_utils.FACIAL_LANDMARKS_IDXS["left_eye"]
(rStart, rEnd) = face_utils.FACIAL_LANDMARKS_IDXS["right_eye"]
cap = cv2.VideoCapture(0)
while True:
ret, frame = cap.read()
gray = cv2.cvtColor(frame, cv2.COLOR_BGR2GRAY)
rects = detector(gray, 0)
for rect in rects:
shape = predictor(gray, rect)
shape = face_utils.shae_to_np(shape)
leftEye = shape[lStart:lEnd]
rightEye = shape[rStart:rEnd]
ear = (leftEAR + rightEAR) / 2.0
leftEyeHull = cv2.convexHull(leftEye)
rightEyeHull = cv2.convexHull(rightEye)
cv2.drawContours(frame, [leftEyeHull], -1, (0,255,0), 1)
cv2.drawContours(frame, [rightEyeHull], -1, (0,255,0), 1)
left = rect.left()
top = rect.top()
right = rect.right()
bottom = rect.bottom()
cv2.rectangle(frame, (left,top),(right,bottom),(0,255,0), 3)
if ear < EYE_AR_THRESH:
cv2.putText(frame,"Warning",(150,30),
cv2.FONT_HERSHEY_SIMPLEX,0.7,(0,0,255), 2)
cv2.imshow("Frame", frame)
print(len(rects))
if cv2.waitKey(1) & 0xFF == ord('q'):
break
cv2.destroyAllWindows()
'''
EYE_AR_THRESH的值可以自己调试修改,我用的是0.25比较准确
我其实就是修改了这位大佬的条件语句罢了。
在发表的时候代码是纯手打的(原谅我是新人不知道怎么复制过来),
可能会出现一些缩进错误,敬请原谅!
'''