二元一次方程

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练习

输入参数,求出二元一次方程的解

import math
def quadratic(a, b, c):
    if (b*b - 4*a*c) < 0:
        return
    elif (b*b - 4*a*c) == 0:
        x1 = -b/2/a
        x2 = -b/2/a
    elif (b*b - 4*a*c) > 0:
        x1 = (-b + math.sqrt(b*b - 4*a*c))/2/a
        x2 = (-b - math.sqrt(b*b - 4*a*c))/2/a
    return x1, x2

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转载自blog.csdn.net/MHeartWGO/article/details/85840576