#Leetcode# 387. First Unique Character in a String

https://leetcode.com/problems/first-unique-character-in-a-string/

Given a string, find the first non-repeating character in it and return it's index. If it doesn't exist, return -1.

Examples:

s = "leetcode"
return 0.

s = "loveleetcode",
return 2.

Note: You may assume the string contain only lowercase letters.

代码:

class Solution {
public:
    int firstUniqChar(string s) {
        int len = s.length();
        unordered_map<char, int> mp;
        int ans = -1;
        
        for(int i = 0; i < len; i ++)
            mp[s[i]] ++;
        
        for(int i = 0; i < len; i ++) {
            if(mp[s[i]] == 1) {
                ans = i;
                break;
            }
        }
        return ans;
    }
};

  

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转载自www.cnblogs.com/zlrrrr/p/10339719.html
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