第二期训练题白银组:08

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在这里插入图片描述
cin,getline()可以连续读取包含空格的字符数组,直至遇见结束符。
ac的c++代码如下:

#include <iostream>
using namespace std;
int main()
{
	int n;
	cin >> n;
	getchar();
	int *a = new int[n];
	int *e = new int[n];
	int *I = new int[n];
	int *o = new int[n];
	int *u = new int[n];
	for (int i = 0;i < n; i++)
	{
		a[i] = 0, e[i] = 0, I[i] = 0, o[i] = 0, u[i] = 0;
		char p[101];
		cin.getline(p,101);
		int j = 0;
		for (; j < 101&&p[j]!='\0'; j++)
		{
			if (p[j] == 'a')
				a[i]++;
			if (p[j] == 'e')
				e[i]++;
			if (p[j] == 'i')
				I[i]++;
			if (p[j] == 'o')
				o[i]++;
			if (p[j] == 'u')
				u[i]++;
		}
	}
	for (int i = 0; i < n; i++)
	{
		if (i + 1 < n)
			cout << "a:" << a[i] << endl << "e:" << e[i] << endl << "i:" << I[i] << endl << "o:" << o[i] << endl << "u:" << u[i] << endl << endl;
		else
			cout << "a:" << a[i] << endl << "e:" << e[i] << endl << "i:" << I[i] << endl << "o:" << o[i] << endl << "u:" << u[i]<<endl;
	}
	delete a, e, I, o, u;
	return 0;
}

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转载自blog.csdn.net/Go_Joe/article/details/84962716