JavaScript刷LeetCode -- 652. Find Duplicate Subtrees [Medium]

一、题目

  Given a binary tree, return all duplicate subtrees. For each kind of duplicate subtrees, you only need to return the root node of any one of them.

  Two trees are duplicate if they have the same structure with same node values.

二、题目大意

  找出二叉树中相同的子树。

三、解题思路

  递归记录遍历子树,以子树的节点路径为key记录相同子树出现的次数。

四、代码实现

const findDuplicateSubtrees = root => {

  const ans = []
  if (!root) {
    return ans
  }

  // 记录所有的路径
  const m = {}
  help(root)

  return ans

  function help (root) {
    if (!root) {
      return
    }

    const path = `${root.val},${help(root.left)},${help(root.right)}`

    m[path] = m[path] || 0
    if (m[path]++ === 1) {
      ans.push(root)
    }
    return path
  }
}

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转载自blog.csdn.net/dai_qingyun/article/details/86469894