oracle数据库建立transTitle(俩个Function,一个Type)20170622

一直在用transTitle翻译字段,结果却不知道它怎么建立的,记下来慢慢研究


prompt

prompt Creating type STRSPLIT
prompt ======================
prompt
CREATE OR REPLACE TYPE 数据库用户名.strSplit IS TABLE OF VARCHAR2 (4000)
/


prompt
prompt Creating function SPLITSTR
prompt ==========================
prompt
CREATE OR REPLACE FUNCTION 数据库用户名.splitStr(p_string IN VARCHAR2, p_delimiter IN VARCHAR2)
    RETURN strSplit
    PIPELINED
AS
    v_length   NUMBER := LENGTH(p_string);
    v_start    NUMBER := 1;
    v_index    NUMBER;
BEGIN
    WHILE(v_start <= v_length)
    LOOP
        v_index := INSTR(p_string, p_delimiter, v_start);


        IF v_index = 0
        THEN
            PIPE ROW(SUBSTR(p_string, v_start));
            v_start := v_length + 1;
        ELSE
            PIPE ROW(SUBSTR(p_string, v_start, v_index - v_start));
            v_start := v_index + 1;
        END IF;
    END LOOP;


    RETURN;
END splitstr;
/


prompt
prompt Creating function TRANSTITLES
prompt =============================
prompt
CREATE OR REPLACE FUNCTION 数据库用户名.transTitles(
       data IN VARCHAR2,
       tableName IN VARCHAR2,
       columnId IN VARCHAR2,
       columnName IN VARCHAR2
) RETURN VARCHAR2 IS
  titles VARCHAR2(200);
  CURSOR cur_ids IS SELECT column_value FROM TABLE(splitstr(data, ','));
  cur_row cur_ids%ROWTYPE;
BEGIN
  titles := '';
  FOR cur_row IN cur_ids LOOP
    EXECUTE IMMEDIATE 'select ''' || titles || '''||' || columnName || '||'',''' || ' from ' || tableName ||
            ' where ' || columnId || ' = ''' || cur_row.column_value || '''' INTO titles;
  END LOOP;
  RETURN(substr(titles, 0, length(titles) - 1));
END transTitles;
/

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转载自blog.csdn.net/Ape55/article/details/73603969