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题目链接
给定一个包括 n 个整数的数组 nums 和 一个目标值 target。找出 nums 中的三个整数,使得它们的和与 target 最接近。返回这三个数的和。假定每组输入只存在唯一答案。
思路
遍历三个数字,一个数字顺序遍历,另外两个采用二分法遍历
代码
class Solution:
def threeSumClosest(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: int
"""
if len(nums) < 3:
raise Exception('input error')
nums.sort()
threeNums = nums[0] + nums[1] + nums[2]
differ = abs(threeNums - target)
ans = threeNums
for i in range(len(nums) - 2):
low = i + 1
high = len(nums) - 1
while(low < high):
threeNums = nums[i] + nums[low] + nums[high]
if abs(threeNums - target) < differ:
differ = abs(threeNums - target)
ans = threeNums
if threeNums == target:
return target
elif threeNums < target:
while low < high and nums[low + 1] == nums[low]:
low += 1
low += 1
else:
while low < high and nums[high - 1] == nums[high]:
high -= 1
high -= 1
return ans