Given n non-negative integers representing the histogram's bar height where the width of each bar is 1, find the area of largest rectangle in the histogram.
Above is a histogram where width of each bar is 1, given height = [2,1,5,6,2,3]
.
The largest rectangle is shown in the shaded area, which has area = 10
unit.
For example,
Given heights = [2,1,5,6,2,3]
,
return 10
.
栈中存储的是上一个比当前高度小的条形的下标,用于计算下一个矩形的底长i-s.top()-1,若栈为空则底长为i。
注意考虑有连续重复高度的条形时,记录的永远是最后一个条形的下标,因为循环时已经将前面大于等于它的下标pop掉了。
整体思路参考博客:http://www.cnblogs.com/grandyang/p/4322653.html
class Solution { public: int largestRectangleArea(vector<int>& heights) { int res = 0; stack<int> s; heights.push_back(0); for(int i=0;i<heights.size();) { if(s.empty()||heights[s.top()]<heights[i]) s.push(i++); else { int temp=s.top(); s.pop(); int d=(s.empty()?i:i-s.top()-1); res=max(res,heights[temp]*d); } } return res; } };