Leetcode804.Unique Morse Code Words (莫尔斯电码重复)

International Morse Code defines a standard encoding where each letter is mapped to a series of dots and dashes, as follows: "a" maps to ".-""b" maps to "-...""c" maps to "-.-.", and so on.

For convenience, the full table for the 26 letters of the English alphabet is given below:

[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]

Now, given a list of words, each word can be written as a concatenation of the Morse code of each letter. For example, "cba" can be written as "-.-..--...", (which is the concatenation "-.-." + "-..." + ".-"). We'll call such a concatenation, the transformation of a word.

Return the number of different transformations among all words we have.

Example:
Input: words = ["gin", "zen", "gig", "msg"]
Output: 2
Explanation: 
The transformation of each word is:
"gin" -> "--...-."
"zen" -> "--...-."
"gig" -> "--...--."
"msg" -> "--...--."

There are 2 different transformations, "--...-." and "--...--.".

Note:

  • The length of words will be at most 100.
  • Each words[i] will have length in range [1, 12].
  • words[i] will only consist of lowercase letters.

国际摩尔斯密码定义一种标准编码方式,将每个字母对应于一个由一系列点和短线组成的字符串, 比如: "a" 对应 ".-""b" 对应 "-...""c" 对应 "-.-.", 等等。

为了方便,所有26个英文字母对应摩尔斯密码表如下:

[".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]

给定一个单词列表,每个单词可以写成每个字母对应摩尔斯密码的组合。例如,"cab" 可以写成 "-.-..--...",(即 "-.-." + "-..." + ".-"字符串的结合)。我们将这样一个连接过程称作单词翻译。

返回我们可以获得所有词不同单词翻译的数量。

例如:
输入: words = ["gin", "zen", "gig", "msg"]
输出: 2
解释: 
各单词翻译如下:
"gin" -> "--...-."
"zen" -> "--...-."
"gig" -> "--...--."
"msg" -> "--...--."
共有 2 种不同翻译, "--...-." 和 "--...--.".
注意:
  • 单词列表words 的长度不会超过 100
  • 每个单词 words[i]的长度范围为 [1, 12]
  • 每个单词 words[i]只包含小写字母。
public class Solution {
	 public int uniqueMorseRepresentations(String[] words) {
	        String[] codes = {".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."};
	        TreeSet<String> set = new TreeSet<>();
	        for(String word: words){
	            StringBuilder res = new StringBuilder();
	            for(int i = 0 ; i < word.length() ; i ++)
	                res.append(codes[word.charAt(i) - 'a']);
	            set.add(res.toString());
	        }
	        return set.size();
	    }
}

测试代码

public class Test {
	public static void main(String[] args) {
		String[] a = { "gin", "zen", "gig", "msg" };
		Solution solution = new Solution();
		System.out.println(solution.uniqueMorseRepresentations(a));
	}
}

 运行结果

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转载自blog.csdn.net/qq_26891141/article/details/85225261