版权声明:本文为博主原创文章,遵循 CC 4.0 BY-SA 版权协议,转载请附上原文出处链接和本声明。
自己的做法:
把其变为字典:
def uniqueMorseRepresentations(words):
di={'a':".-",'b':"-...",'c':"-.-.",'d':"-..",'e':".",'f':"..-.",'g':"--.",'h':"....",'i':"..",'j':".---",'k':"-.-",'l':".-..",'m':"--",'n':"-.",'o':"---",'p':".--.",'q':"--.-",'r':".-.",'s':"...",'t':"-",'u':"..-",'v':"...-",'w':".--",'x':"-..-",'y':"-.--",'z':"--.."}
result=[]
for w in words:
temp=""
for i in w:
temp=temp+di[i]
result.append(temp)
result2=[]
for i in result:
if i not in result2:
result2.append(i)
return len(result2)
exm= ["gin", "zen", "gig", "msg"]
print(uniqueMorseRepresentations(exm))
别人的做法:
class Solution:
def uniqueMorseRepresentations(self, words: List[str]) -> int:
result_letter = ""
result_word = []
morse_arr = [".-","-...","-.-.","-..",".","..-.","--.","....","..",".---","-.-",".-..","--","-.","---",".--.","--.-",".-.","...","-","..-","...-",".--","-..-","-.--","--.."]
for word in words:
for letter in word:
result_letter = result_letter +morse_arr[ord(letter)-97]
result_word.append(result_letter)
result_letter = ""
return(len(set(result_word)))
ord()函数是 chr() 函数(对于8位的ASCII字符串)或 unichr() 函数(对于Unicode对象)的配对函数,它以一个字符(长度为1的字符串)作为参数,返回对应的 ASCII 数值,或者 Unicode 数值,如果所给的 Unicode 字符超出了你的 Python 定义范围,则会引发一个 TypeError 的异常。
a=97