[LEETCODE] #2 linked list add two numbers

https://leetcode.com/problems/add-two-numbers/

You are given two non-empty linked lists representing two non-negative integers. The digits are stored in reverse order and each of their nodes contain a single digit. Add the two numbers and return it as a linked list.

You may assume the two numbers do not contain any leading zero, except the number 0 itself.

Example:

Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.

* Definition:

/**
   https://leetcode.com/problems/add-two-numbers/
   * @param {ListNode} l1
   * @param {ListNode} l2
   * @return {ListNode}
   */
function ListNode(val) {
    this.val = val;
    this.next = null;
}

* Solution:

ListNode.prototype._tail = function() {
    for (var p = this; p.next != null; p = p.next) {}
    return p;
};

ListNode.prototype.add = function(val) {
    var node = new ListNode(val);
    this._tail().next = node;
    return this;
};

var deepClone = function(t, e) {
	"number" != typeof e && (e = 10);
	var i, n = e - 1;
	if (e > 0)
		if (t instanceof Date)
			i = new Date,
			i.setTime(t.getTime());
		else if (t instanceof Array) {
			i = [];
			for (var o = 0, s = t.length; s > o; o++)
				i[o] = this.deepClone(t[o], n)
		} else if ("object" == typeof t) {
			i = {};
			for (var r in t)
				if (t.hasOwnProperty(r)) {
					var a = t[r];
					i[r] = this.deepClone(a, n)
				}
		} else
			i = t;
	else
		i = t;
	return i
}

ListNode.prototype.plus = function(/* ListNode */ al) /* :ListNode */ {
	var carry = 0, cur = 0, list = null;
	if (this == null) return deepClone(al);
	if (al == null) return deepClone(this);
	
	var p, q;
	for (p = this, q = al; p != null && q != null; p = p.next, q = q.next) {
		cur = p.val + q.val + carry;
		9 < cur ? (cur -= 10, carry = 1) : (carry = 0);
		if (null === list) {list = new ListNode(cur);}
		else {list.add(cur);}
	}
	// console.log('carry='+carry);
	// console.log(p, q);
	for (; p != null; p = p.next) {
		cur = p.val + carry;
		9 < cur ? (cur -= 10, carry = 1) : (carry = 0);
		list.add(cur);
	}
	for (; q != null; q = q.next) {
		cur = q.val + carry;
		9 < cur ? (cur -= 10, carry = 1) : (carry = 0);
		list.add(cur);
	}
	if (carry > 0) {
		list.add(carry);
	}
	
	return list;
};

ListNode.prototype.reverse = function() {
	if (this.next === null) {
		return this;
	}
	var head = this, prev = null, cur = head, next;
	while (cur !== null) {
		next = cur.next;  // save next
		head = cur;  // move cur to head
		cur.next = prev;
		prev = cur;  // iterate
		cur = next;
	}
	return head;
};

// main function
var addTwoNumbers = function(l1, l2) {
	return l1.plus(l2);
};

* test:

// test
ListNode.prototype.forEach = function(/* function */ c) {
    for (var p = this, i = 0; p != null; p = p.next, ++i) {
		c(p.val, i);
    }
};

ListNode.prototype.toString = function() {
    var a = [];
    a.push('[');
    this.forEach(function(v, i) {
		a.push(v);
		a.push(',');
    });
    a[a.length-1] = ']';
    return a.join('');
};

function llist(/* Array */ a) {
    var l = new ListNode(a[0]);
    for (var i = 1; i < a.length; i++) {
		l.add(a[i]);
    }
    return l;
}

// [5] + [5]
// var a1 = [9,8], a2 = [1];
// var a1 = [1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1], a2 = [5,6,4];
// var l1 = llist([2,4,3]), l2 = llist([5,6,4]);
// [6,6,4,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,1]
var a1 = [1], a2 = [9, 9];
var l1 = llist(a1), l2 = llist(a2);
console.log(addTwoNumbers(l1, l2).toString());

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转载自blog.csdn.net/fareast_mzh/article/details/84591307