用递归实现数制转换(2-16)

 

public static String baseString(int n,int b) {
		String str="",
		strBt="0123456789abcdef";
		if(n<=0) {
			return "";
		}else {
			str=baseString(n/b,b);
			return str+strBt.charAt(n%b);
		}		
	}