训练题1

题目链接:https://vjudge.net/problem/CodeForces-118A

String Task

Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:

deletes all the vowels,
inserts a character “.” before each consonant,
replaces all uppercase consonants with corresponding lowercase ones.
Vowels are letters “A”, “O”, “Y”, “E”, “U”, “I”, and the rest are consonants. The program’s input is exactly one string, it should return the output as a single string, resulting after the program’s processing the initial string.

Help Petya cope with this easy task.

Input
The first line represents input string of Petya’s program. This string only consists of uppercase and lowercase Latin letters and its length is from 1 to 100, inclusive.

Output
Print the resulting string. It is guaranteed that this string is not empty。
我们看到题目有三个要求:
1、清除字符串里所有的元音字母
2、在每个辅音字母前面加一个“.”
3、把字符串里的大写字母换成对应的小写字母
笔者的代码如下:

#include<iostream>
using namespace std;
int main()
{
	char *p;
	p = new char[101];
	cin >> p;  //输入字符串
	for (int i = 0;p[i]!='\0'; i++)
	{
		int k = 1;
		if (p[i] >= 65 && p[i] <= 90)p[i] += 32;  //把大写字母全部换为小写字母
		if (p[i] == 'a' || p[i] == 'e' || p[i] == 'i' || p[i] == 'o' || p[i] == 'u' || p[i] == 'y' ||
			p[i] == 'A' || p[i] == 'E' || p[i] == 'I' || p[i] == 'O' || p[i] == 'U' || p[i] == 'Y')k = 0;
		if (k)cout << '.' << p[i];  //对辅音字母进行输出并加"."
	}
	delete[]p;
	system("pause");
}

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转载自blog.csdn.net/weixin_43997690/article/details/84874168
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