1)
assume cs:code, ds:data
data segment
db 12
db 0,0 ; 前一个字节用于保存商,后一个字节用于保存余数
data ends
code segment
start:
mov ax,data
mov ds,ax ; 补全指令,使得ds <-- data段地址
mov ah,0
mov al,ds:[0] ; ax <-- data段字节单元的被除数12
mov bl,10
div bl
mov ds:[1],al ; 补全代码,让商保存到data段注释中指定的单元
mov ds:[2],ah ; 补全代码,让余数保存到data段注释中指定的单元
mov ah,2
mov dl,ds:[1] ; 补全代码,使得dl <-- data段中保存的商的字节单元数值
add dl,30h; 补全代码,使得dl中的数值转换为数字字符
int 21h
mov ah,2
mov dl,ds:[2] ; 补全代码,使得dl <-- data段中保存余数的字节单元数值
add dl,30h ; 补全代码,使得dl中的数值转换为数字字符
int 21h
mov ax,4c00h
int 21h
code ends
end start
2)
assume cs:code, ds:data
data segment
db 12,35,96,55,67
db 10 dup(0)
data ends
code segment
start:
mov ax,data
mov ds,ax
mov bx,0
mov cx,5
s: mov al,ds:[bx]
mov ah,0
mov dl,10
div dl
or ah,00110000b
or al,00110000b
mov ds:[bx+5],al
mov ds:[bx+6],ah
mov ah,2
mov dl,ds:[bx+5]
int 21h
mov ah,2
mov dl,ds:[bx+6]
int 21h
mov ah,2
mov dl,' '
int 21h
inc bx
loop s
mov ax,4c00h
int 21h
code ends
end start
3)
assume ds:data, cs:code
data segment
db 'welcome to masm!'
db 2H,24H,71H
data ends
stacksg segment
dw 8 dup(0)
stacksg ends
code segment
start: mov ax,data
mov ds,ax
mov ax,0b800H
mov es,ax
mov cx,3
mov di,0
mov si,06E0h
s0: push cx
mov al,ds:[16+di]
mov bx,0
mov cx,16
s1: mov dl,ds:[bx]
mov byte ptr es:[si],dl
mov byte ptr es:[si+1],al
inc bx
add si,2
loop s1
add si,128
inc di
pop cx
loop s0
mov ax,4c00h
int 21h
code ends
end start