python Scipy求解非线性方程组和数值积分

#求解非线性方程组2x1-x2^2=1,x1^2-x2=2
from scipy.optimize import fsolve #导入求解方程组的函数
from scipy import integrate
def func(x:list):
    x1=x[0]
    x2=x[1]
    xy=[2*x1-x2**2-1,x1**2-x2-2]
    result=fsolve(xy,x)  #输入初始值,并求解
    return result
def g(y):
    return (1-y**2)**0.5
pi_2,err=integrate.quad(g,-1,1)  #积分结果和误差
print(pi_2*2)

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转载自blog.csdn.net/qq_24726509/article/details/84727111
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