用函数模板求一维数组的最大值和最小值

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://blog.csdn.net/qq_30432997/article/details/84578786
//第一次作业:  
//用函数模板求一维数组中的最大和最小值。  
#include <iostream>  
#include "string.h"  
using namespace std;  
template <class T>  
void maxmin(T* x, int n, T* max, T* min)//函数模板  
{  
    T tempmax = x[0];  
    T tempmin = x[0];  
    for (int i = 1; i < n; i++)  
    {  
        if (x[i] > tempmax)tempmax = x[i];  
        if (x[i] < tempmin)tempmin = x[i];  
    }  
    *max = tempmax;  
    *min = tempmin;  
}  
  
void maxmin(char** x, int n, char** max, char** min)//同名显式函数  
{  
    char* tempmax = x[0];  
    char* tempmin = x[0];  
    for (int i = 1; i < n; i++)  
    {  
        if (strcmp(x[i], tempmax) > 0) tempmax = x[i];  
        if (strcmp(x[i], tempmin) < 0)tempmin = x[i];  
    }  
    *max = tempmax;  
    *min = tempmin;  
}  
int main()  
{  
    int intArray[] = { 1, 2, 3, -4, 5, 6, 49 };  
    int intMax, intMin;  
    maxmin(intArray, 7, &intMax, &intMin);  
    cout <<"最大值: "<< intMax << "  最小值: " << intMin << endl;  
  
    double doubleArray[] = { 1.1, 2.2, 3.3, -4.4, 5.5, 6.6, 0.0 };  
    double doubleMax, doubleMin;  
    maxmin(doubleArray, 7, &doubleMax, &doubleMin);  
    cout << "最大值: "<<doubleMax << "  最小值: " << doubleMin << endl;  
  
    char* strArray[]= {"today","is","a","happy","day"};  
    char* strMax, *strMin;  
    maxmin(strArray, 5, &strMax, &strMin);  
    cout << "最大值: "<<strMax << "  最小值: " << strMin << endl;  
  
    return 0;  
} 

 

 

程序输出:

最大值: 49  最小值: -4

最大值: 6.6  最小值: -4.4

最大值: today  最小值: a

请按任意键继续. . .

猜你喜欢

转载自blog.csdn.net/qq_30432997/article/details/84578786
今日推荐