20进制的大数加法

地球人用十进制是因为有十根手指,外星人有20根呢?

#include <cstdio>
#include <cstdlib>
#include <iostream>
#include <cstring>
#include <cmath>
#define MIN(a,b) (a<b?a:b)
#define MAX(a,b) (a>b?a:b)
#define mem(a,b) memset(a,b,sizeof(a))
using namespace std;

char str1[110], str2[110];
int num1[110], num2[110], num[110];
int main(){
    int i, j;
    int len1, len2, len;
    while(scanf("%s%s", str1, str2)){

        mem(num1, 0);
        mem(num2, 0);
        mem(num, 0);
        len1 = strlen(str1);
        len2 = strlen(str2);
        len = MAX(len1, len2);

        /*转换为20进制*/
        for(i=0; i<len1; ++i){
            if(str1[i]>='0'&&str1[i]<='9')
                num1[len1-i] = str1[i]-'0';
            else num1[len1-i] = str1[i]-'a'+10;
        }

        for(i=0; i<len2; ++i){
            if(str2[i]>='0'&&str2[i]<='9')
                num2[len2-i] = str2[i]-'0';
            else num2[len2-i] = str2[i]-'a'+10;
        }

        /*相加*/
        for(i=1; i<=len+1; ++i){
            num[i] = num[i-1]/20+num1[i]+num2[i];
            num[i-1] = num[i-1]%20;
        }
          //去除前面的0
        for(i=len+1; i>1; --i)
            if(num[i])
                break;

        for (j=i; j>0; --j){
            if(num[j]>9)
                printf("%c", num[j]-10+'a');
            else    printf("%d", num[j]);
        }
        printf("\n");
    }

    return 0;
}

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转载自blog.csdn.net/phthon1997/article/details/83472060