//交换两个数组的内容
#include <stdio.h>
int main(){
int a[5] = { 3, 4, 5, 6, 7 };
int b[5] = { 234, 456, 565, 444, 777 };
int t;
int i = 5;
for (i = 0; i < 5; i++){
t = a[i]; a[i] = b[i]; b[i] = t;
printf("%d\t", a[i]);
if (i == 4){
printf("\n");
}
}for (i = 0; i < 5; i++){
printf("%d\t", b[i]);
}
system("pause");
return 0;
}
//计算1/1-1/2+1/3…-1/100
#include <stdio.h>
int main(){
int i;
double sum = 0;
for (i = 1; i <= 100; i++){
if (i % 2 == 0){
sum = sum - 1.0 / i;
}
else{
sum = sum + 1.0 / i;
}
}
printf("%f\n", sum);
system("pause");
return 0;
}
//9出现的次数
#include <stdio.h>
int main(){
int num, hundred, ten, unit, count = 0;
for (num = 1; num <= 100;++num){
hunderd = num / 100;
ten = (num - hundred * 100) / 10;
unit = num - hundred * 100 - ten * 10;
if (hundred == 9){
count++;
}if (ten == 9){
count++;
}if (unit == 9){
count++;
}
}
printf("1到100中9出现的个数:%d\n", count);
system("pause");
return 0;
}